Ask Question
28 March, 04:49

a 50.0 mL sample of KCl requires 22.40 mL of 0.0229 M Pb (NO3) 2 in order to completely titrate it. What is the Molarity of the KCl sample?

+5
Answers (1)
  1. 28 March, 08:11
    0
    0.02052M

    Explanation:

    First, we need to write a balanced equation for the reaction. This is illustrated below:

    2KCl + Pb (NO3) 2 → 2KNO3 + PbCl2

    The following were obtained from the question:

    Molarity of Pb (NO3) 2 = 0.0229M

    Volume of Pb (NO3) 2 = 22.40 = 22.4/1000 = 0.0224L

    Number of mole of Pb (NO3) 2 = ?

    Recall:

    Mole = Molarity x Volume

    Mole of Pb (NO3) 2 = 0.0229x0.0224

    Mole of Pb (NO3) 2 = 5.13x10^-4mole

    From the equation,

    1mole of Pb (NO3) 2 required 2moles KCl.

    Therefore, 5.13x10^-4mole of Pb (NO3) 2 will require = 5.13x10^-4x2 = 1.026x10^-3mole of KCl.

    Now we can use this amount (i. e 1.026x10^-3mole) to find the molarity of KCl. This is illustrated below:

    Mole of KCl = 1.026x10^-3mole

    Volume of KCl = 500mL = 50/1000 = 0.05L

    Molarity = ?

    Molarity = mole / Volume

    Molarity of KCl = 1.026x10^-3/0.05

    Molarity of KCl = 0.02052M
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “a 50.0 mL sample of KCl requires 22.40 mL of 0.0229 M Pb (NO3) 2 in order to completely titrate it. What is the Molarity of the KCl sample? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers