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9 December, 01:30

Given the balanced chemical equation, SiO2 (s) + 4 HF (g) → SiF4 (g) + 2 H2O (l) ΔH°rxn = - 184 kJ Determine the mass (in grams) of HF (g) must react when 345 kJ of energy is released.

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  1. 9 December, 05:11
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    mass HF = 150.05 g

    Explanation:

    SiO2 (s) + 4HF (g) → SiF4 (g) + 2H2O (l)

    ⇒ Q = (ΔH°rxn * mHF) / (mol HF * MwHF)

    ∴ MwHF = 20.0063 g/mol

    ∴ mol HF = 4 mol

    ∴ ΔH°rxn = - 184 KJ

    ∴ Q = 345 KJ

    mass HF (mHF):

    ⇒ mHF = (Q * mol HF * MwHF) / ΔH°rxn

    ⇒ mHF = (345 KJ * 4mol HF * 20.0063 g/mol) / 184 KJ

    ⇒ mHF = 150.05 g HF
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