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26 March, 21:20

A liter of water was found to contain 10 mg of benzene (C6H6). What is the concentration of benzene in mg/L, ppm, and molarity?

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  1. 26 March, 22:16
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    10 mg/L: C₆H₆

    10 ppm: C₆H₆

    1.28*10⁻⁴ M : [C₆H₆]

    Explanation:

    A liter of water was found to contain 10 mg of benzene (C6H6).

    This can be understood as mg/L concentration. 10 mg of benzene are contained in 1L of solution.

    If we want to write concentration of ppm, we assume μg/mL

    So let's convert 10 mg to μg

    10 mg. 1000 = 10000 μg

    and 1L = 1000 mL

    So μg/mL → 10000 μg / 1000 mL = 10

    Molarity is mol/L

    We know that the volume is 1L so let's convert the 10 mg of benzene to moles. (mass (g) / molar mass)

    0.01 g / 78 g/mol = 1.28*10⁻⁴ moles
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