Under what conditions does an increase in temperature turn a nonspontaneous process into a spontaneous process?

Choose one or more:

a. ΔH 0

b. ΔH > 0, ΔS > 0

c. ΔH > 0, ΔS < 0

d. ΔH < 0, ΔS < 0

(What I'm trying to figure out is if you need to consider T being negative OR positive to start)

Answer:ΔH 0

Explanation:

Consider ∆G = ∆H-T∆S

If ∆H is negative and and ∆S is positive, when T is increased, T∆S becomes more positive until the result of the difference between ∆H-T∆S becomes negative. Remember that a reaction is only spontaneous when ∆G is negative. Hence under these conditions, ∆G becomes negative and the reaction becomes spontaneous.