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19 July, 01:34

A beaker has 0.2 M of Na2SO4. What will be the concentration of sodium and sulfate ions?

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  1. 19 July, 05:23
    0
    Na+-0.0648M

    SO4²-0.1352M

    Explanation:

    First find the R. A. M of the sodium sulphate

    (23*2) + (32) + (16*4) = 142

    Find the portion of sodium ions=46/142*0.2

    =0.0648M

    Sulphate=

    0.2-0.0648=0.1352M
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