Ask Question
3 August, 07:22

How many grams of Al were reacted with excess HCl if 2.34 L of hydrogen gas were collected at STP in the following reaction2Al + 6HCl - -> 2AlCl3 + 3H2

+1
Answers (1)
  1. 3 August, 08:48
    0
    1.87 g of Al were reacted

    Explanation:

    We must apply the Ideal Gases law to solve the amount of moles of H₂ produced at STP

    T = 273 K

    P = 1 atm

    P. V = n. R. T

    1 atm. 2.34 L = n. 0.082. 273 K

    (1 atm. 2.34 L) / (0.082. 273 K) = n

    0.104 moles = n

    Now we can find the moles of Al with the reaction. As ratio is 3:2 we have to make a rule of three to determine the moles we used.

    3 moles of H₂ came from 2 moles of Al

    0.104 moles of H₂ would come from (0.104. 2) / 3 = 0.0693 moles of Al

    Finally we can know the mass of Al we used (moles. molar mass)

    0.0693 mol. 26.98 g/mol = 1.87 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many grams of Al were reacted with excess HCl if 2.34 L of hydrogen gas were collected at STP in the following reaction2Al + 6HCl - -> ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers