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7 March, 03:59

1. How many moles are in 493.4 grams of calcium phosphide?

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  1. 7 March, 06:09
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    Formula = Ca3P2

    RAM of; Ca = 40 x 3 = 120g, P = 30 x 2 = 60g. 120 + 60 = 180g

    Mole = 493.4g / 180g = 2.74mols
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