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19 March, 02:12

Calculate the molarity of each of the following solutions.

(a) 7.49 g of methanol (CH3OH) in 1.50 * 102 mL of solution:

(b) 9.18 g of calcium chloride (CaCl2) in 2.20 * 102 mL of solution:

(c) 6.51 g of naphthalene (C10H8) in 85.2 mL of benzene solution:

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  1. 19 March, 05:00
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    a) 1.56 M

    b) 0.376 M

    c) 0.599 M

    Explanation:

    Step 1: Molarity

    Molarity = Number of moles / volume in L

    Number of moles = mass / Molar mass

    (a) 7.49 g of methanol (CH3OH) in 1.50 * 10² mL of solution

    Volume = 1.50 * 10² mL = 0.15 L

    Molar mass of CH3OH = 32.04 g/mol

    Number of moles CH3OH = 7.49 grams / 32.04 g/mol

    Moles of CH3OH = 0.234 moles

    Molarity CH3OH = 0.234 moles / 0.15 L

    Molarity CH3OH = 1.56 M

    (b) 9.18 g of calcium chloride (CaCl2) in 2.20 * 10² mL of solution:

    Volume = 2.20 * 10² mL = 0.22L

    Molar mass of CaCl2 = 110.98 g/mol

    Number of moles CaCl2 = 9.18 grams / 110.98 g/mol

    Moles CaCl2 = 0.0827 moles

    Molarity CaCl2 = 0.0827 moles / 0.22L

    Molarity CaCl2 = 0.376 M

    (c) 6.51 g of naphthalene (C10H8) in 85.2 mL of benzene solution:

    Volume = 85.2 mL = 0.0852L

    Molar mass of C10H8 = 128.17 g/mol

    Number of moles C10H8 = 6.51 grams / 128.17 g/mol

    Moles C10H8 = 0.051 moles

    Molarity C10H8 = 0.051 moles / 0.0852 L

    Molarity C10H8 = 0.599 M
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