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19 November, 07:23

A monolayer containing 3.19 * 10 - 6 g of oleic acid has an area of 20.0 cm 2. The density of oleic acid is 0.895 g / mL. What is the thickness of the monolayer (the length of an oleic acid molecule) ?

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  1. 19 November, 09:13
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    1.78 * 10⁻⁷ cm

    Explanation:

    Using,

    Density = Mass / Volume

    Given:

    Area = 20.0 cm²

    Density = 0.895 g/mL

    Mass = 3.19 * 10⁻⁶ g

    Applying in the density formula as:

    0.895 g/mL = 3.19 * 10⁻⁶ g / Volume (ml)

    Volume = 3.56 * 10⁻⁶ mL

    Since, 1 mL = cm³

    So, Volume = 3.56 * 10⁻⁶ cm³

    Thickness (height) of monolayer = ?

    Also, Volume = area x thickness

    So,

    Thickness = Volume/Area = 3.56 * 10⁻⁶ cm³ / 20.0 cm² = 1.78 * 10⁻⁷ cm
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