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25 October, 02:09

while doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm^3. the accepted value for the density of aluminum is 2.70 g/cm^3. The accepted value for density of aluminum is 2.70 g/cm^3. What was the student's percent error?

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  1. 25 October, 03:24
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    Percent error = 5.6%

    Explanation:

    Given dа ta:

    Measured value of density by students = 2.85 g/cm³

    Accepted density of aluminium = 2.70 g/cm³

    Percent error = ?

    Solution:

    Formula:

    Percent error = [ Measured value - accepted value / accepted value ] * 100

    Now we will put the values in formula:

    Percent error = [ 2.85 g/cm³ - 2.70 g/cm³ / 2.70 g/cm³ ] * 100

    Percent error = [0.15/2.70 g/cm³ ] * 100

    Percent error = 0.056 * 100

    Percent error = 5.6%
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