A chemist determines by measurements that 0.0900 moles of bromine liquid participate in a chemical reaction. Calculate the mass of bromine liquid that participates. Be sure your answer has the correct number of significant digits.

There will participate 14.4 grams of bromine

Explanation:

Step 1: Data given

Liquid bromine is Br2

Numbers of moles of bromine liquid = 0.0900 moles

Molar mass of Br = 79.9 g/mol

Molar mass of Br2 = 2 * 79.9 = 159.8 g/mol

Step 2: Calculate the mass of bromine that will participate

Mass = moles * molar mass

Mass bromine = 0.0900 moles * 159.8 g/mol

Mass bromine = 14.4 grams

There will participate 14.4 grams of bromine

14.4 grams of bromine liquid participate on the reaction

Explanation:

Bromine liquid is also a diatomic molecule as the gas form.

Br₂

Molar mass = 159.8 g/m

Molar mass. mol = mass

159.8 g/m. 0.0900 mol = 14.4 grams