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Chemistry
Rosa Ruiz
23 August, 13:54
Calculate OH - given H3 O + = 1.40 * 10^-4 M
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Payton Pittman
23 August, 16:36
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3.16 X 10^-11 M is the [OH-] concentration when H3O + = 1.40 * 10^-4 M.
Explanation:
data given:
H30 + = 1.40 X 10^-4 M/
Henderson Hasslebalch equation to calculate pH=
pH = - log10 (H30+)
putting the values in the equation:
pH = - log 10 (1.40 X 10^-4 M)
pH = 3.85
pH + pOH = 14
pOH = 14 - 3.85
pOH = 10.15
The OH - concentration from the pOH by the equation:
pOH = - log10[OH-]
10.5 = - log10[OH-]
[OH-] = 10^-10.5
[OH-] = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 * 10^-4 M.
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