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23 August, 13:54

Calculate OH - given H3 O + = 1.40 * 10^-4 M

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  1. 23 August, 16:36
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    3.16 X 10^-11 M is the [OH-] concentration when H3O + = 1.40 * 10^-4 M.

    Explanation:

    data given:

    H30 + = 1.40 X 10^-4 M/

    Henderson Hasslebalch equation to calculate pH=

    pH = - log10 (H30+)

    putting the values in the equation:

    pH = - log 10 (1.40 X 10^-4 M)

    pH = 3.85

    pH + pOH = 14

    pOH = 14 - 3.85

    pOH = 10.15

    The OH - concentration from the pOH by the equation:

    pOH = - log10[OH-]

    10.5 = - log10[OH-]

    [OH-] = 10^-10.5

    [OH-] = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 * 10^-4 M.
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