Ask Question
31 January, 15:12

The volume of a gas is 17.5 mL at 29◦C and

0.863 atm. What will the volume be at 13◦C

and 0.994 atm?

+2
Answers (1)
  1. 31 January, 19:05
    0
    Answer: V = 14.4 mL

    Explanation:

    In this case, we'll use the ideal gas formula:

    PV = nRT

    Where:

    P: pressure in atm

    V: volume in liter

    n: moles

    R: gas constant (In this case 0.082 L atm/mol K)

    T: temperature in K

    We have data for the gas at first, so we can actually calculate the moles used, which will be constant even at different temperature and pressure. Let's calculate the moles:

    n = PV/RT

    Before we do this, let's convert the volume and temperature:

    T = 29 + 273 = 302 K

    V = 17.5 / 1000 = 0.0175 L

    Now the moles:

    n = 0.863 * 0.0175 / 0.082 * 302 = 0.00061 moles

    with these moles, let's convert the temperature to K:

    T2 = 13 + 273 = 286 K

    and to calculate the volume:

    V = nRT/P

    so:

    V = 0.00061 * 0.082 * 286 / 0.994

    V = 0.0144 L or simply 14.4 mL
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The volume of a gas is 17.5 mL at 29◦C and 0.863 atm. What will the volume be at 13◦C and 0.994 atm? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers