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20 August, 16:15

Determine the concentration of a solution made by dissolving 44.0 g of calcium chloride (CaCl2) in 0.30 L of solution. SHOW YOUR WORK for credit. Partial credit is awarded! Correct answers with no work will not receive credit. Reminder of the the steps: 1. Identify what you know and what you want, and the units. Known: 0.30 L, 44.0 g CaCl2 Want: molarity (mol / L) 2. Find the amount of CaCl2 in moles. molar Mass of CaCl2 = 110.98 g/mol. Formula: Moles = grams / molar mass 3. Use dimensional analysis to set up and solve equation. Formula: M = mol solute / L solution

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  1. 20 August, 17:04
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    [CaCl₂] = 1.32 M

    Explanation:

    We know the volume of solution → 0.30 L

    We know the mass of solute → 44 g of CaCl₂

    Let's convert the mass of solute to moles.

    44 g. 1 mol / 110.98 g = 0.396 moles

    Molarity (mol/L) → 0.396 mol / 0.3 L = 1.32 M
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