Ask Question
21 May, 19:50

The observed rotation of 2.0 g of a compound in 50 mL of solution in a polarimeter tube 20 cm long is + 138°. What is the specific rotation of the compound?

+1
Answers (1)
  1. 21 May, 20:41
    0
    +1725

    Explanation:

    The specific rotation can be calculated using the formula:

    Specific Rotation = Observed Rotation / (l * C)

    Where l is the path length in decimeters (20 cm / 10), 2 dm; and C is the concentration of the compound in mg/mL (2.0g / 50mL), 0.04 g/mL.

    Putting the data we're left with:

    Specific Rotation = + 138 / (2 * 0.04) = + 1725
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The observed rotation of 2.0 g of a compound in 50 mL of solution in a polarimeter tube 20 cm long is + 138°. What is the specific rotation ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers