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9 April, 16:14

The reaction A + 2B → products has been found to have the rate law, rate = k[A]2[B]. While holding the concentration of A constant, the concentration of B is increased from x to 3x. Predict by what factor the rate of reaction increases.

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Answers (2)
  1. 9 April, 18:46
    0
    Factor of 3.

    Explanation:

    Rate law is given as:

    r = k [A]² [B]

    Given:

    [Bo] = x

    [B1] = 3x

    Let [Ao] = [A1] = t

    Since the concentration of A is held constant, the rate law is written as:

    r = t² [B]

    Initially,

    ro = t² [x]

    Then,

    r1 = t² [3x]

    ro/[x] = r1/[3x]

    r1 = 3 * ro
  2. 9 April, 19:06
    0
    The rate of reaction triples up if the concentration of B is tripled.

    Explanation:

    The rate law is given as

    r = k [A]² [B]

    The rate is 2nd order with respect to [A] and first order with respect to [B]

    If the concentration of A is held constant, the rate law can be written as

    r = K [B]

    where K = k [A]²

    If initially the concentration of B is x

    r = K [x]

    If it is then changed to 3x, the rate becomes

    r (new) = K [3x] = 3 K [x]

    r (new) = 3 * r

    Hence, the rate of reaction triples up if the concentration of B is tripled.
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