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15 February, 01:39

Determine the volume of hexane that contains 5.33 * 1022 molecules of hexane. The density of hexane is 0.6548 g/mL and its molar mass is 86.17 g/mol. Determine the volume of hexane that contains 5.33 * 1022 molecules of hexane. The density of hexane is 0.6548 g/mL and its molar mass is 86.17 g/mol. 13.5 mL 11.6 mL 7.40 mL 8.59 mL 12.4 mL

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  1. 15 February, 02:19
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    11.6 mL is the volume for 5.33 * 10²² molecules of hexane

    Explanation:

    We analyse dа ta:

    5.33 * 10²² molecules of hexane

    0.6548 g/mL

    86.17 g/mol

    First of all, we determine the moles of hexane that contain 5.33 * 10²² molecules

    6.02*10²³ molecules are contained in 1 mol

    5.33 * 10²² molecules must be contained in (5.33 * 10²². 1) / NA = 0.088 moles

    Now we convert the moles to mass → 0.088 mol. 86.17 g/m = 7.63 g

    Finally we apply density to determine the volume

    Density = mass / volume → Volume = Mass / Density

    Volume = 7.63 g / 0.6548 g/mL = 11.6 mL
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