What is the specific heat of a substance if 6527 J are required to raise the temperature of a 312 g sample by 15 degrees Celsius?

1.395J/g°C

Explanation:

The following were obtained from the question:

Q = 6527J

M = 312g

ΔT = 15°C

C = ?

Q = MCΔT

C = Q/MΔT

C = 6527 / (312 x 15)

C = 1.395J/g°C

The specific heat capacity of the substance is 1.395J/g°C