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9 October, 09:46

What mass of carbon dioxide is produced from the complete combustion of 8.00*10-3 g of methane? Express your answer with the appropriate units.

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  1. 9 October, 10:38
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    22*10-3 g

    Explanation:

    Combustion equation of methane:

    CH4 + 2O2 → CO2 + 2H2O

    Given dа ta:

    mass of methane = 8.00 * 10-3 g

    mass of carbon dioxide=?

    Solution 1:

    m (CH4) = 8.00 * 10-3 g

    v=m / M

    v (CH4) = m (CH4) / M (CH4)

    v (CH4) = 8.00 * 10-3 g / 16 g / mol

    v (CH4) = 0.5 * 10-3 mol

    according to balance chemical equation:

    v (CH4) : v (CO2) = 1:1

    v (CH4) = v (CO2)

    M (CO2) = 44 g/mol

    m (CO2) = M (CO2) * v (CO2)

    m (CO2) = 44 g/mol * 0.5 * 10-3 mol = 22*10-3 g

    Second method:

    molecular weight of methane = 16 g/mol

    molecular weight of carbon dioxide = 44 g/mol

    mass of methane = 8.00*10-3 g

    mass of carbon dioxide=?

    Solution:

    mass of carbon dioxide = mass of methane * molecular weight of carbon dioxide / molecular weight of methane

    mass of carbon dioxide = 8.00*10-3 g * 44 g/mol / 16 g/mol

    mass of carbon dioxide = 22 * 10-3 g
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