Potassium hydroxide reacts with sulfuric acid how much potassium sulfate is produced from

10.75 g of sulfuric acid

19 g of K₂SO₄ was produced.

Explanation:

2 KOH + H₂SO₄ →K₂SO₄ + 2 H₂O

Now if we have 10.75 g of H₂SO₄ we can calculate the number of moles as,

Wt / M. wt = 10.75 / 98 = 0.109 moles

Now we can calculate the number of moles of K₂SO₄ as that:

1 mole of H₂SO₄react gives 1 mole K₂SO₄

0.109 mole of H₂SO₄ gives (x)

x (number of moles of K₂SO₄ = 1 * 0.109 / 1 = 0.109 mole

now we can calculate the wt as,

wt = no. moles * M. wt

wt = 0.109 * 174.259 = 18.966 g = 19 g