Iodine, I2 (s), is more soluble in dichloromethane, CH2Cl2 (l), than water because:

A. the intermolecular forces are similar in both dichloromethane and iodine.

B. the dipole-dipole forces in dichloromethane are much stronger than the dispersion forces in iodine.

C. Iodine is polar and dichloromethane has a large number of hydrogen bonds.

D. Both iodine and dichloromethane have strong, ion-dipole interactions

A. the intermolecular forces are similar in both dichloromethane and iodine.

Explanation:

Solubility is determined by the principle, "like dissolves like".

i. e., if a compound is polar then it will dissolve in a polar compound only, and

if a compound is non - polar then it will dissolve in a non - polar compound only.

As,

Non polar compounds, have similar interaction, and hence gets dissolved, and similarly,

polar compounds have similar dipole - dipole interaction, and hence gets dissolved.

From the question,

Iodine, I₂ (s), is more soluble in dichloromethane, CH₂Cl₂ (l), as both are non - polar in nature and hence due to similar interaction, are soluble.

Water is polar in nature and therefore less soluble in Iodine, I₂ (s).