Ask Question
6 July, 00:52

Water (2350 g) is heated until it just begins to boil. If the water absorbs 5.83*105 J of heat in the process, what was the initial temperature of the water? Express your answer with the appropriate units.

+5
Answers (1)
  1. 6 July, 03:30
    0
    40.7062 °C

    Explanation:

    Let the initial temperature = x °C

    Boiling temperature of water = 100 °C

    Using,

    Q = m C * ΔT

    Where,

    Q is the heat absorbed in the temperature change from x °C to 100 °C.

    C gas is the specific heat of the water = 4.184 J/g °C

    m is the mass of water

    ΔT = (100 - x) °C

    Given,

    Mass = 2350 g

    Q = 5.83 * 10⁵ J

    Applying the values as:

    Q = m C * ΔT

    5.83 * 10⁵ = 2350 * 4.184 * (100 - x)

    x, Initial temperature = 40.7062 °C
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Water (2350 g) is heated until it just begins to boil. If the water absorbs 5.83*105 J of heat in the process, what was the initial ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers