Ask Question
12 February, 06:49

Cobalt-60 is a radioactive isotope used to treat cancers of the brain and other tissues. A gamma ray emitted by an atom of this isotope has an energy of 0.700 MeV (million electron volts; 1 eV = 1.602 * 10-19 J). What is the frequency (in Hz) and the wavelength (in m) of this gamma ray? Enter your answers in scientific notation.

+3
Answers (1)
  1. 12 February, 08:48
    0
    1.69 x 10 ²⁰ Hz

    1.77 x 10⁻¹² m

    Explanation:

    For any radiation, its energy is give by

    E = hν = h c/λ where

    h = Planck's constant,

    ν = Frequency,

    λ = wavelength,

    c = speed of light

    We have all the information so plug the values, being careful with the units.

    E = h ν∴ ν = E/h

    = (0.700 MeV x 1x10⁶ eV/MeV x 1.602 x 10⁻¹⁹ J/eV) / 6.626 x 10⁻³⁴ J s

    = 1.69 x 10 ²⁰ s⁻¹ = 1.69 x 10 ²⁰ Hz (1 Hz = 1s⁻¹)

    λ = c / ν = (3 x 10^8 m/s) / 1.69 x 10 ²⁰ s⁻¹ = 1.77 x 10⁻¹² m
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Cobalt-60 is a radioactive isotope used to treat cancers of the brain and other tissues. A gamma ray emitted by an atom of this isotope has ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers