In performing this week's bromination reaction, if you were to start with 126 mg of acetanilide (135.17 g/mol), calculate the theoretical yield of 4-bromoacetanilide (214.06 g/mol), in mg. Assume an excess of bromine. Enter your answer as digits only, no units, using the proper number of significant figures.

Question

Chemistry

Joslyn Zhang

29 August, 01:13

In performing this week's bromination reaction, if you were to start with 126 mg of acetanilide (135.17 g/mol), calculate the theoretical yield of 4-bromoacetanilide (214.06 g/mol), in mg. Assume an excess of bromine. Enter your answer as digits only, no units, using the proper number of significant figures.

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Answers (1)

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Gia Owens · Answer 1

Theoretical yield of C8H8BrNO:

In moles

0.000945

In grams

0.204

Explanation:

Theoretical yield of a reaction is defined as the quantity of the product obtained from the complete conversion of a limiting reactant in a chemical reaction. Theoretical yield can be expressed as grams or moles.

Equation of reaction:

C8H9NO + Br2 - -> C8H8BrNO + HBr

Since C8H9NO is the limiting reagent, 1 mole of C8H9NO reacted to form 1 mole of C8H8BrNO

Mass of C8H9NO = 129 mg

= 0.129 g.

Molar mass of C8H9NO = 135.17 g/mol.

Number of moles of C8H9NO = mass/molar mass.

= 0.129/135.17

= 0.00095 moles of C8H9NO

Since 1 mole of C8H9NO yielded 1 mole of C8H8BrNO

Therefore, 0.000954 moles of C8H8BrNO

Theoretical yield (in grams) = molar mass * number of moles

= 214.06 * 0.00095

= 0.204 of C8H8BrNO