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28 July, 13:46

You have 100.0 mL of a solution of hydrochloric acid that has a pH of 3.00. You add 100.0 mL of water to this solution. What is the resulting pH of the solution?

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  1. 28 July, 17:13
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    3.30

    Explanation:

    Original volume of the HCl solution = 100.0 mL

    pH of the solution = 3.00

    Concentration of the hydrogen ions can be calculated as:

    pH = - log[H⁺]

    So,

    3 = - log[H⁺]

    [H⁺] = 10⁻³ concentration units.

    For original acid solution:

    C₁ = 10⁻³, V₁ = 100 mL

    For 10% acid solution:

    C₂ = ?, V₂ = 200 mL (100 mL of water is added to 100 mL of original solution)

    Using

    C₁V₁ = C₂V₂

    10⁻³*100 = C₂*200

    C₂ = 0.5*10⁻³ concentration units.

    So,

    pH is:

    pH = - log[H⁺] = - log (0.5*10⁻³) = 3.30
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