What is the molar mass of 37.96 g of gas exerting a pressure of 3.29 on the walls of a 4.60 L container at 375 K?

The molar mass of the gas is 77.20 gm/mole.

Explanation:

The data given is:

P = 3.29 atm, V = 4.60 L T = 375 K mass of the gas = 37.96 grams

Using the ideal Gas Law will give the number of moles of the gas. The formula is

PV = nRT (where R = Universal Gas Constant 0.08206 L. atm / K mole

Also number of moles is not given so applying the formula

n = mass : molar mass of one mole of the gas.

n = m : x (x molar mass) (m mass given)

Now putting the values in Ideal Gas Law equation

PV = m : x RT

3.29 * 4.60 = 37.96/x * 0.08206 * 375

15.134 = 1168.1241 : x

15.134x = 1168.1241

x = 1168.1241 : 15.13

x = 77.20 gm/mol

If all the units in the formula are put will get cancel only grams/mole will be there. Molecular weight is given by gm/mole.