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23 October, 18:26

What is the molar mass of 37.96 g of gas exerting a pressure of 3.29 on the walls of a 4.60 L container at 375 K?

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  1. 23 October, 21:00
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    The molar mass of the gas is 77.20 gm/mole.

    Explanation:

    The data given is:

    P = 3.29 atm, V = 4.60 L T = 375 K mass of the gas = 37.96 grams

    Using the ideal Gas Law will give the number of moles of the gas. The formula is

    PV = nRT (where R = Universal Gas Constant 0.08206 L. atm / K mole

    Also number of moles is not given so applying the formula

    n = mass : molar mass of one mole of the gas.

    n = m : x (x molar mass) (m mass given)

    Now putting the values in Ideal Gas Law equation

    PV = m : x RT

    3.29 * 4.60 = 37.96/x * 0.08206 * 375

    15.134 = 1168.1241 : x

    15.134x = 1168.1241

    x = 1168.1241 : 15.13

    x = 77.20 gm/mol

    If all the units in the formula are put will get cancel only grams/mole will be there. Molecular weight is given by gm/mole.
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