Ask Question
28 May, 00:01

Calculate the nuclear binding energy in mega-electronvolts (MeV) per nucleon for 136 Ba. 136 Ba has a nuclear mass of 135.905 amu. nuclear binding energy per nucleon:

+1
Answers (1)
  1. 28 May, 02:04
    0
    8.194 Mev per nucleon

    Explanation:

    Mass of Barium = 135.905 amu

    number of proton = 56, number of neutron = 80

    Md = (Mp + Mn) - Mb Mp is the mass of proton, Mn is the mass of neutron, Mb is the mass of barium and Md is the mass defect

    Mn = 1.00867 amu Mp = 1.00728 amu

    Md = (56 (1.00728) + 80 (1.00867) = 137.1013 - 135.905 = 1.1963 amu

    Md = 1.1963 * 1 : (6.02214 * 10 ²⁶ amu) = 1.9865 * 10 ⁻²⁷ kg

    Energy = mc² = 1.9865 * 10 ⁻²⁷ kg * (2.99792 * 10 ⁸ m/s) ²

    E = 1.78537 * 10⁻¹⁰ J

    to convert to Mev

    1.78537 * 10⁻¹⁰ * 6241457006000 = 1114.33 Mev

    binding energy per nucleon = 1114.33 / 136 = 8.194 Mev per nucleon
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Calculate the nuclear binding energy in mega-electronvolts (MeV) per nucleon for 136 Ba. 136 Ba has a nuclear mass of 135.905 amu. nuclear ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers