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ChemistryChemistry
30 September, 09:21

Each step in the following process has a yield of 70.0%. CH4+4Cl2⟶CCl4+4HCl CCl4+2HF⟶CCl2F2+2HCl The CCl4 formed in the first step is used as a reactant in the second step. If 2.00 mol CH4 reacts, what is the total amount of HCl produced? Assume that Cl2 and HF are present in excess. moles HCl : mol

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  1. 30 September, 11:36
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    n (HCl) = 1.96 mol

    Explanation:

    CH4+4Cl2⟶CCl4+4HCl

    CCl4+2HF⟶CCl2F2+2HCl

    With ideal yields we will end up with 4 moles of HCl.

    With 70% yields on every stage

    n (HCl) = 0.7*0.7*4=1.96 mol
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Home » Chemistry » Each step in the following process has a yield of 70.0%. CH4+4Cl2⟶CCl4+4HCl CCl4+2HF⟶CCl2F2+2HCl The CCl4 formed in the first step is used as a reactant in the second step. If 2.
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