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24 April, 04:50

The volume of water that must be added in order to dilute 40mL of 9.0M HCl to a concentration of 6.0 M is closest to: (A) 10 mL (B) 20 mL (C) 30 mL (D) 40 mL (E) 60 mL

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  1. 24 April, 08:02
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    We should add 60 mL (option E)

    Explanation:

    Step 1: Data given

    Initial volume = 40 mL = 0.040 L

    Initial molarity = 9.0 M

    New molarity = 6.0 M

    Step 2:

    C1*V1 = C2*V2

    ⇒with C1 = the initial molarity = 9.0 M

    ⇒ with V1 = the initial volume = 0.040 L

    ⇒ with C2 = the new molarity = 6.0 M

    ⇒ with V2 = the new volume

    9.0 * 0.040 = 6.0 * V2

    V2 = 0.06 L = 60 mL

    We should add 60 mL (option E)
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