Ask Question
11 May, 11:45

A compound is 25.9% nitrogen and 74.1% oxygen find the empirical formula

+2
Answers (1)
  1. 11 May, 13:05
    0
    Let suppose the compound weights 100 g,

    Nitrogen = 25.9 % = 25.9 g

    Oxygen = 74.1 % = 74.1 g

    Compound = Nitrogen + Oxygen

    Compound = 25.9 g + 74.1 g = 100g

    Calculate moles of Nitrogen and Oxygen,

    As,

    Mole = mass / M. mass

    For Nitrogen,

    Mole = 25.9 g / 14.0 g/mol

    Mole = 1.85 moles of Nitrogen

    For Oxygen,

    Mole = 74.1 g / 15.999 g/mol

    Mole = 4.631 moles of Oxygen

    Now finding Ratio of Nitrogen to Oxygen,

    Nitrogen : Oxygen

    1.85 : 4.631

    Now,

    Dividing this ratio with 1.85 as it is the lowest number,

    So,

    (1.85 : 1.85) : (4.631 : 1.85)

    1 : 2.50

    Multiply this ratio with 2 so that a whole numbers are obtained

    (1 : 2.50) * 2

    Result:

    2 : 5

    There are 2 Nitrogen atoms and 5 Oxygen atoms in this compound.

    N₂O₅ (Empirical Formula)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A compound is 25.9% nitrogen and 74.1% oxygen find the empirical formula ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers