How many potassium hydroxide (KOH) formula units are present in 6.89 mol of KOH?:

A. 4.1498 * 1024

B. 4.1498 * 1023

C. 8.299 * 1024

D. 8.299 * 1023

To get the number of formula units of the compound, potassium hydroxide (KOH), we must recall that for every mole of ionic compound, the number of fomula units is 6.022 * 10^23 units, or the avogadro's number. Hence, for a 6.89 mol compound, the number of formula units is 4.1498 * 10^24 units. Answer is A.