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14 July, 01:48

A compound is analyzed and found to contain 22.10%Al, 25.40%P, and 52.50%O. What is the empirical formula of the compound?

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  1. 14 July, 03:59
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    We will determine the moles of each element first

    moles = mass / atomic mass

    Atomic weight of Al : 27 g / mol

    Atomic weight of P : 3 1g / mol

    Atomic weight of O : 16 g / mol

    Let the total mass of compound is 100g

    The mass of each element will be

    Al = 22.10 g

    P = 25.40 g

    O = 52.50 g

    Moles of Al = mass / atomic mass = 22.10 / 27 = 0.819

    Moles of P = mass / atomic mass = 25.40 / 31 = 0.819

    Moles of O = mass / atomic mass = 52.50 / 16 = 3.28

    Now we will divide the moles of each element with the lowest moles obtained to obtain a whole number ratio of moles of each element present

    moles of Al = 0.819 / 0.819 = 1

    moles of P = 0.819 / 0.819 = 1

    moles of O = 3.28 / 0.819 = 4

    So the empirical formula will be : AlPO4
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