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17 February, 01:44

A rigid container is divided into two compartments of equal volume by a partition. one compartment contains 1 mole of ideal gas a at 1 atm, and the other contains 1 mole of ideal gas b at 1 atm. calculate the increase in entropy which occurs when the partition between

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  1. 17 February, 04:07
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    The volume of compartment is equal. One compartment has 1 mole of ideal gas a at pressure 1 atm and other compartment have 1 mole of ideal gas b at pressure 1 atm.

    If the partition between the compartment is removed, the volume of gas a with 1 mole become twice of its initial value. Similarly, volume of gas b with 1 mole doubles.

    Change in entropy is calculated as follows:

    For gas a, / Delta S_{a}=Rln/frac{V_{2}}{V_{1}}

    Since, V_{2}=2V_{1}

    Thus,

    /Delta S_{a}=Rln/frac{2V_{1}}{V_{1}}=Rln2

    Similarly, change in entropy for gas b will be / Delta S_{b}=Rln2

    Total entropy will be:

    /Delta S_{a}+/Delta S_{b}=Rln2+Rln2=Rln4
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