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25 December, 07:08

If the pressure of a confined gas doubles and its volume decreases by a factor of four, how will its Kelvin temperature change?

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  1. 25 December, 09:40
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    Answer;

    Temperature halves or decreases by a factor of 2

    Explanation;

    The relationship between pressure, volume, and temperature can be expressed as;

    PV/T

    and we can compare one state to another by this expression;

    P1V1/T1 = P2V2/T2

    in this case, we can say P1, V1 and T1 are all equal to 1 and have the pressure doubled, such that P2 = 2 and the volume decreases by a factor of four, so that V = 1/4; then T2 will be equal to;

    (1) (1) / 1 = (2) (1/4) / T2

    1 = 0.5/T2

    T2 = 0.5 or 1/2

    Temperature will therefore half or decrease by a factor of 2
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