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23 August, 15:26

if you have 0.5 grams of CaCl2 dissolved to make 15mL of solution, what is the molarity of the solution?

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  1. 23 August, 18:31
    0
    0.3M

    Explanation:

    Molarity of a solution is given by;

    M=n/v

    Where;

    n = number of moles of solute = mass of solute / molar mass

    v = volume of solution

    n = mass of CaCl2 / molar mass of CaCl2

    Mass of CaCl2 = 0.5

    Molar mass of CaCl2 = 40 + (2*35.5)

    = 111g/mol

    n = 0.5/111 = 0.0045mol

    volume, v = 15mL = 15/1000 L = 0.015L

    Note that molarity is in mole per liter, hence we convert 15mL to L. 1mL=1/1000L

    M = 0.0045/0.015

    M=0.3mol/L

    Therefore, the molarity of the solution is 0.3M
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