Ask Question
8 July, 16:38

A 39 liter SCUBA tank contains 310 grams of oxygen gas (O2, molar mass = 32.0 g/mol) at 19°C. Calculate the pressure in kiloPascals (kPa).

+5
Answers (1)
  1. 8 July, 20:05
    0
    602.95 kPa.

    Explanation:

    To solve these problems, we can use the general law of ideal gas: PV = nRT.

    where, P is the pressure of the gas in atm.

    V is the volume of the gas in L (V = 39.0 L).

    n is the no. of moles of the gas in mol.

    R is the general gas constant (R = 0.082 L. atm/mol. K).

    T is the temperature of the gas in K (T = 19.0 °C + 273.15 = 292.15 K).

    The volume of the gas = nRT/P.

    P = ? atm, V = 39.0 L, R = 0.082 L. atm/mol. K, n = mass/molar mass = (310.0 g) / (32.0 g/mol) = 9.6875 mo, T = 19.0 °C + 273.15 = 292.15 K.

    ∴ P = nRT/V = (9.6875 mol) (0.082 L. atm/mol. K) (292.15 K) / (39.0 L) = 5.95 atm.

    To convert fom atm to kPa:

    101.325 kPa = 1.0 atm.

    ∴ P = 5.95 atm x (101.325 kPa / 1.0 atm) = 602.95 kPa.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 39 liter SCUBA tank contains 310 grams of oxygen gas (O2, molar mass = 32.0 g/mol) at 19°C. Calculate the pressure in kiloPascals (kPa). ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers