A chemist is working on a reaction represented by this chemical equation:

FeCl2 + 2KOH → Fe (OH) 2 + 2KCl.

If the chemist uses 4.15 moles of iron (II) chloride and 3.62 moles of potassium hydroxide, how many moles of iron (II) hydroxide will the reaction produce?

A. 1.81 mol

B. 3.62 mol

C. 4.15 mol

D. 7.24 mol

Question

Chemistry

Leila

5 July, 01:30

A chemist is working on a reaction represented by this chemical equation:

FeCl2 + 2KOH → Fe (OH) 2 + 2KCl.

If the chemist uses 4.15 moles of iron (II) chloride and 3.62 moles of potassium hydroxide, how many moles of iron (II) hydroxide will the reaction produce?

A. 1.81 mol

B. 3.62 mol

C. 4.15 mol

D. 7.24 mol

+4

Answers (2)

Know the Answer?

Rockette · Answer 1

It's A. 1.81 mol. This answer is on Plato.

#PlatoLivesMatter

Veronica Murillo · Answer 2

Answer is: A. 1.81 mol.

Balanced chemical reaction: FeCl₂ + 2KOH → Fe (OH) ₂ + 2KCl.

n (FeCl₂) = 4.15 mol; amount of iron (II) chloride.

n (KOH) = 3.62 mol; amount of potassium hydroxide, limiting reactant.

From chemical reaction: n (KOH) : n (Fe (OH) ₂) = 2 : 1.

n (Fe (OH) ₂) = n (KOH) : 2.

n (Fe (OH) ₂) = 3.62 mol : 2.

n (Fe (OH) ₂) = 1.81 mol; amount of iron (II) hydroxide.