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27 November, 06:50

A sample of gas y occupies 500 L at the pressure of 80 KPa. after changing the volume of the sample the pressure of it is 400 KPa what is the new volume of the gas?

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  1. 27 November, 08:41
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    This is a boyles law question. You have to use the equation P1V1=P2V2, where P is pressure and V is volume, and 1 represents initial values while 2 represent final values. So, in this instant P1=80kPa, V1=500L, and P2=400kPa. Since you know all except one variable, you can plug them into the boyles law equation to solve for V2.

    (80) (500) = (400) V2

    V2=100L

    So the new volume is 100 liters. This makes sense because you would expect the volume to decrease quite a bit since the pressure has increase so much.
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