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4 March, 19:13

A 20.0 mL sample of hydrochloric acid was neutralized with 58.4 mL of 0.250 M NaOH, in a titration.

a. Write the balanced chemical equation for the reaction,

b. What is the concentration of the hydrochloric acid?

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Answers (1)
  1. 4 March, 21:50
    0
    M = 0.73

    Explanation:

    a)

    HCl + NaOH - > NaCl + H2O

    b)

    M = mol solute / L solution

    mol NaOH = M * L solution mol NaOH = 0.250 M * 0.0584L =

    0.0146 mol NaOH

    mol NaOH = mol HCl

    M = mol HCl / L solution

    M = 0.0146 mol HCl/0.02 L M = 0.73
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