A 20.0 mL sample of hydrochloric acid was neutralized with 58.4 mL of 0.250 M NaOH, in a titration.

a. Write the balanced chemical equation for the reaction,

b. What is the concentration of the hydrochloric acid?

M = 0.73

Explanation:

a)

HCl + NaOH - > NaCl + H2O

b)

M = mol solute / L solution

mol NaOH = M * L solution mol NaOH = 0.250 M * 0.0584L =

0.0146 mol NaOH

mol NaOH = mol HCl

M = mol HCl / L solution

M = 0.0146 mol HCl/0.02 L M = 0.73