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9 November, 02:47

If 4520 kj of heat is needed to boil a sample of water, what is the mass of water

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  1. 9 November, 05:14
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    1,085g of water

    Explanation:

    If we have the value 4520kj is because the question is related to Energy and heat capacity. In this case, the law and equation that we use is the following:

    Q = m*C*Δt where;

    Q in the heat, in this case: 4520kj

    m is the mas

    Δt = is the difference between final-initial temperature (change of temperature), in this exercise we don't have temperatura change.

    In order to determine the mass, I will have the same equation but finding m

    m = Q/C*Δt without m=Q/C

    So: m = 4,520J/4.18J/g°C

    m = 1,0813 g
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