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29 April, 16:53

What is the molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water?

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  1. 29 April, 20:00
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    1 litre of water is equal to 1000.0 g of water

    we need to find molality of a solution containing 10.0 g of dissolved in Na₂S0₄1000.0 g of water

    1. For that find the molar mass

    Na: 2 x 22.99 = 45.98

    S: 32.07

    O: 4 x 16 = 64

    Total molar mass is 142.05

    We have to find the number of moles, y

    To find the number of moles divide 10.0g by 142.05 g/mol.

    So the number of moles is 0.0704 moles.

    For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.

    The molarity would end up being 0.0704 M

    The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is 0.0704 M
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