If the value of kc at 25oc is 3.7108, and the equilibrium concentrations for n2 and h2 are 0.000105 m and 0.0000542 m, respectively, use the expression in question 5 to calculate the equilibrium concentration of nh3.

Equation of decomposition of ammonia:

N2+3H2->2NH3

Euilibrium constant:

Kc = (NH3) ^2 / ((N2) ((H2) ^3))

As concentration of N2=0.000105, H2=0.0000542

so equation will become:

3.7 = (NH3) ^2 / (0.000105) * (0.0000542) ^3

NH3=√ (3.7*0.000105 * (0.0000542) ^3)

NH3=7.8*10⁻⁹

So concentration of ammonia will be 7.8*10⁻⁹.