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9 April, 15:03

If the value of kc at 25oc is 3.7108, and the equilibrium concentrations for n2 and h2 are 0.000105 m and 0.0000542 m, respectively, use the expression in question 5 to calculate the equilibrium concentration of nh3.

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  1. 9 April, 15:23
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    Equation of decomposition of ammonia:

    N2+3H2->2NH3

    Euilibrium constant:

    Kc = (NH3) ^2 / ((N2) ((H2) ^3))

    As concentration of N2=0.000105, H2=0.0000542

    so equation will become:

    3.7 = (NH3) ^2 / (0.000105) * (0.0000542) ^3

    NH3=√ (3.7*0.000105 * (0.0000542) ^3)

    NH3=7.8*10⁻⁹

    So concentration of ammonia will be 7.8*10⁻⁹.
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