Ask Question
22 October, 00:26

The first-order rate constant for the decomposition of n2o5, 2n2o5 (g) →4no2 (g) + o2 (g) at 70∘c is 6.82*10-3 s-1. suppose we start with 2.00*10-2 mol of n2o5 (g) in a volume of 2.3 l. you may want to reference (page) section 14.4 while completing this problem. part a how many moles of n2o5 will remain after 4.0 min?,

+2
Answers (1)
  1. 22 October, 01:22
    0
    The rate constant for 1st order reaction is

    K = (2.303 / t) log (A0 / A)

    Where, k is rate constant

    t is time in sec

    A0 is initial concentration

    (6.82 * 10-3) * 240 = log (0.02 / A)

    1.63 = log (0.02 / A)

    -1.69 - log A = 1.63

    Log A = - 0.069

    A = 0.82

    Hence, 0.82 mol of A remain after 4 minutes.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The first-order rate constant for the decomposition of n2o5, 2n2o5 (g) →4no2 (g) + o2 (g) at 70∘c is 6.82*10-3 s-1. suppose we start with ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers