Ask Question
30 August, 09:00

SO2Cl2 (g) ⇌SO2 (g) + Cl2 (g) Kc=2.99*10-7 at 227 ∘C You may want to reference (Page) Section 15.8 while completing this problem. Part A If a reaction mixture initially contains 0.186 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?

+1
Answers (1)
  1. 30 August, 10:57
    0
    2.36*10^-4 M

    Explanation:

    The following data were obtained from the question:

    Equilibrium constant, Kc = 2.99*10^-7

    Concentration of SO2Cl2, [SO2Cl2] = 0.186 M

    Concentration of Cl2, [Cl2] = ?

    Next, we shall write the balanced equation for the reaction. This is given below:

    SO2Cl2 (g) ⇌SO2 (g) + Cl2 (g)

    Next, we shall we shall construct the initial concentration and equilibrium table (ICE). This is illustrated below:

    Initial concentration:

    [SO2Cl2] = 0.186 M

    [SO2] = 0

    [Cl2] = 0

    During reaction:

    [SO2Cl2] = - y

    [SO2] = + y

    [Cl2] = + y

    Equilibrium:

    [SO2Cl2] = 0.186 - y

    [SO2] = y

    [Cl2] = y

    Next, we shall determine the value of y in order to obtain the concentration of Cl2. This can be achieved by doing the following:

    Kc = [SO2] [Cl2] / [SO2Cl2]

    Kc = 2.99*10^-7

    [SO2Cl2] = 0.186 M

    [SO2] = y

    [Cl2] = y

    2.99*10^-7 = (y * y) / 0.186

    Cross multiply

    y * y = 2.99*10^-7 * 0.186

    y² = 2.99*10^-7 * 0.186

    Take the square root of both side:

    y = √ (2.99*10^-7 * 0.186)

    y = 2.36*10^-4

    Therefore, the concentration of Cl2, [Cl2] = y = 2.36*10^-4 M
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “SO2Cl2 (g) ⇌SO2 (g) + Cl2 (g) Kc=2.99*10-7 at 227 ∘C You may want to reference (Page) Section 15.8 while completing this problem. Part A If ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers