Calculate the resulting ph obtained by mixing 16.5 g hcl and 22.6 g nacl in water to create 482 l solution.

Answer;

pH = 3.03

Explanation;

NaCl is a neutral salt and does not affect the pH.

moles HCl = g HCl / MM

= 16.5 / 36.5

= 0.452 equivalent to moles H+

Molarity H + = moles H + / L

= 0.452 / 482

= 0.000938 M

Hence; pH = - log[H+]

= - log (0.000938)

= 3.03