If the reaction starts with 20 moles of NaF, how many moles of AlF3 would you produce?

AL (NO3) 3 (aq) + NaF (aq) - -> 3 NaNO3 (aq) + ALF3 (aq)

6.67 moles of AlF3

Explanation:

The first step is always to put down the equation of the reaction:

Al (NO3) 3 (aq) + 3NaF (aq) - -> 3 NaNO3 (aq) + AlF3 (aq)

Now recall that the stoichiometry of the reaction is very important in solving problems like this. From the balanced chemical reaction equation we can be able to deduce the amount of product obtained from a particular amount of reactants as shown.

From the balanced reaction equation;

3 moles of NaF yields 1 mole of AlF3

Therefore 20 moles of NaF will yield 20 * 1 / 3 = 6.67 moles of AlF3

Therefore, 6.67 moles of AlF3 is produced.