Ask Question
14 April, 06:20

What is the total energy needed to boil 255 grams of water, given that the

ΔH vaporization = 40,650 J/mol

+1
Answers (1)
  1. 14 April, 06:27
    0
    575,000 J

    Explanation:

    1) Convert the mass of water into number of moles

    Molar mass of water: 18.015 g/mol

    Number of moles, n = mass in grams / molar mass

    n = 255 g / 18.015 g/mol = 14.15 mol

    2) Use the formula E = n * ΔH vap

    This is, you have to multiply the molar ΔH vaporization by the number of moles to find the total energy to boil the given amount of water.

    E = 14.15 mol * 40,650 J/mol = 575,395.5 J

    3) Round to the correct number of significant figures.

    The mass of water is the measurement with the least number of significant figures (3), so you must report the answer with 3 significant figures,

    E = 575,000 J ← answer
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the total energy needed to boil 255 grams of water, given that the ΔH vaporization = 40,650 J/mol ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers