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25 February, 01:13

Tim is grilling burgers for dinner. He uses 15.0g of propane. Given that the combustion of propane releases 2,220 kJ/mol and that the molecular weight of propane is 44.097 g/mol, calculate the enthalpy of the propane used for dinner.

A) 755 kJ

B) 1,390 kJ

C) 2,130 kJ

D) 6,530 kJ

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Answers (2)
  1. 25 February, 02:19
    0
    A.

    Hopefully it works
  2. 25 February, 02:23
    0
    Heat Enthalpy used = 755 Kilojoules

    Explanation:

    15 grams propane = (15g/44.097g·mol⁻¹) = 0.3402mol propane

    Heat Enthalpy used = 0.3402mol X 2,220Kj/mol = 755 Kilojoules
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