What is the concentration, in mass percent (m/m), of a solution prepared from 50.0 g nacl and 150.0 g of water?

Mass of solute (m1) = 50.0 g

mass of solvent (m2) = 150.0 g

Therefore:

m/m = (m1 / m1 + m2)

m/m = (50.0 / 50.0 + 150.0)

m/m = (50.0 / 200)

m/m = 0.25

Answer: 25%m/m

Explanation: The concentration of a solution (in mass percent) is the mass of the solute divided by the mass of the solution, in the given case, the solute is NaCl and its mass is 50.0 g, and the mass of the solution will be the mass of the solute plus the mass of the solvent (water):

mass of the solution = mass of NaCl + mass of water

mass of the solution=50.0 g + 150.0 g

mass of the solution=200.0 g

concentration (%m/m) = 100*mass of the solute/mass of the solution

concentration (%m/m) = 100*50.0g/200.0 g

concentration (%m/m) = 25%m/m