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30 November, 18:12

Pipettes are used when measuring the volumes of liquids with high degree of precision. The following volumes were obtained during the calibration of a 10.00 mL pipette: 10.15 mL, 9.95 mL, 9.99 mL, and 10.02 mL. Calculate the standard deviation for these measurements.

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  1. 30 November, 20:17
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    0.075

    Explanation:

    First obtain the mean of the measurement;

    Mean = 10.15 + 9.95 + 9.99 + 10.02/4 = 10.03

    Then obtain d^2 = (mean-score) ^2 for each score;

    (10.15-10.03) ^2 = 0.0144

    (9.95-10.03) ^2 = 0.0064

    (9.99-10.03) ^2 = 0.0016

    (10.02-10.03) ^2 = 0.0001

    ∑d^2 = 0.0144 + 0.0064 + 0.0016 + 0.0001

    ∑d^2 = 0.0225

    Variance = ∑d^2/N = 0.0225/4 = 0.005625

    Standard deviation = √0.005625

    Standard deviation = 0.075
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